# Convert number: 521 in Roman numerals, how to write?

## Latest conversions of Arabic numbers to Roman numerals

 521 = DXXI Dec 06 14:23 UTC (GMT) 10,592 = (X)DXCII Dec 06 14:23 UTC (GMT) 372 = CCCLXXII Dec 06 14:23 UTC (GMT) 27 = XXVII Dec 06 14:23 UTC (GMT) 33 = XXXIII Dec 06 14:22 UTC (GMT) 3,905,940 = (M)(M)(M)(C)(M)(V)CMXL Dec 06 14:22 UTC (GMT) 221,119 = (C)(C)(X)(X)MCXIX Dec 06 14:22 UTC (GMT) 15,368 = (X)(V)CCCLXVIII Dec 06 14:22 UTC (GMT) 979 = CMLXXIX Dec 06 14:22 UTC (GMT) 400,040 = (C)(D)XL Dec 06 14:22 UTC (GMT) 7,000 = (V)MM Dec 06 14:22 UTC (GMT) 997,566 = (C)(M)(X)(C)(V)MMDLXVI Dec 06 14:22 UTC (GMT) 89,711 = (L)(X)(X)(X)M(X)DCCXI Dec 06 14:21 UTC (GMT) converted numbers, see more...

## The set of basic symbols of the Roman system of writing numerals

• ### (*) M = 1,000,000 or |M| = 1,000,000 (one million); see below why we prefer this notation: (M) = 1,000,000.

(*) These numbers were written with an overline (a bar above) or between two vertical lines. Instead, we prefer to write these larger numerals between brackets, ie: "(" and ")", because:

• 1) when compared to the overline - it is easier for the computer users to add brackets around a letter than to add the overline to it and
• 2) when compared to the vertical lines - it avoids any possible confusion between the vertical line "|" and the Roman numeral "I" (1).

(*) An overline (a bar over the symbol), two vertical lines or two brackets around the symbol indicate "1,000 times". See below...

Logic of the numerals written between brackets, ie: (L) = 50,000; the rule is that the initial numeral, in our case, L, was multiplied by 1,000: L = 50 => (L) = 50 × 1,000 = 50,000. Simple.

(*) At the beginning Romans did not use numbers larger than 3,999; as a result they had no symbols in their system for these larger numbers, they were added on later and for them various different notations were used, not necessarily the ones we've just seen above.

Thus, initially, the largest number that could be written using Roman numerals was:

• MMMCMXCIX = 3,999.