CCCLXV - MLXXVI + MMCCX =

CCC - I + MCC

CCC - I + MCC

MD -

I =

MCCCCLXXXXVIIIII -

I =

MCCCCLXXXXVIIII

I =

MCCCCLXXXXVIIIII -

I =

MCCCCLXXXXVIIII

365 - 1,076 + 2,210 = 1,499

How to add and subtract the Roman numerals:

MMMDCCCVIII - MXXVIII + MMMCCLXX + DCCLXIII + MMMDCCCXLVIII = ? | Oct 29 22:07 UTC (GMT) |

CCCLXV - MLXXVI + MMCCX = ? | Oct 29 22:07 UTC (GMT) |

DCCCLXXXVI - ML - CDLXXIII = ? | Oct 29 22:07 UTC (GMT) |

CDLX + MMDCLXXVI + MMCCCLXVI = ? | Oct 29 22:07 UTC (GMT) |

VI + CCLXXXIV - CXIV + LII + CCXXXIX = ? | Oct 29 22:07 UTC (GMT) |

MDCCIII - MDCCCXCVI - MDCLI - MDCLIV + MCCLXXVIII = ? | Oct 29 22:07 UTC (GMT) |

DCCXXIX + MCMLXXIII = ? | Oct 29 22:07 UTC (GMT) |

MMCLXIV + MMDCCCXXXIX + MCCLXIX = ? | Oct 29 22:07 UTC (GMT) |

CDXV - CDXCVI = ? | Oct 29 22:07 UTC (GMT) |

MV + MCCCXLV = ? | Oct 29 22:07 UTC (GMT) |

DXVII + DCCLXVI + MXXII - CLXXXV + DCCC = ? | Oct 29 22:07 UTC (GMT) |

DXXVI - CXL - CCCXCVIII - DLI + CLXXII = ? | Oct 29 22:07 UTC (GMT) |

MMDCCXCIX - MMDLIV - MXIV + MMMCXXXIV - MDCCCXLI = ? | Oct 29 22:07 UTC (GMT) |

All the Roman numerals calculations: what our visitors added or subtracted, online operations... |

- Let's learn by an example:
#### XC + MCMLIII + CCXIX - MCCXLVIII - XC = ?

- 90 + 1.953 + 219 - 1.248 - 90 = ? The Romans did not have the Hindu-Arabic numbers

- Matching numerals / symbols are colored the same.
- XC + MCMLIII + CCXIX - MCCXLVIII - XC = MCMLIII + CCXIX - MCCXLVIII;

- Matching numerals / symbols are colored the same.
- MCMLIII + CCXIX - MCCXLVIII = CML + XIX - XLV;

do not mix subtractive and additive groups symbols.

- For example, the numerals XI and IV:
- XI is an additive group - largest symbol on the left, down to the smallest on the right - to calculate the value add up the symbols: XI = X + I = 10 + 1 = 11;
- IV is a subtractive group - a smaller symbol precedes a larger one - to calculate the value subtract the first symbol from the second: IV = V - I = 5 - 1 = 4.
- When subtracting the two numerals, XI - IV = (uncompact the subtractive) XI - IIII = X - III = VIIIII - III = VII (= 7), CORRECT. But if you cross out the common symbol regardless of the fact that it is part of a subtractive group: XI - IV = X - V = VV - V = V (= 5), WRONG.

- Subtractive notation = a group of two numerals, one of a lower value preceding another larger one, the only allowed ones are: IV, IX, XL, XC, CD, CM, M(V), M(X), (X)(L), (X)(C), (C)(D), (C)(M) - to calculate the value subtract the first symbol from the second.
- Additive notation = a group of two or more numerals, equal or sorted in descending order from high to low, largest symbol on the left, down to the smallest on the right - to calculate the value add up the symbols.
- CML: CM = M - C = D CCCCC - C = D CCCC = DCCCC; CML = DCCCCL;
- XIX: IX = X - I = V IIIII - I = V IIII = VIIII; XIX = XVIIII;
- XLV: XL = L - X = XXXXX - X = XXXX; XLV = XXXXV;

- Catenate the positive numerals together.
- DCCCCL + XVIIII = DCCCCLXVIIII;

- DCCCCLXVIIII - XXXXV = DCCCCLIIII - XXX;

- Symbols converted, in additive notation: L = XXXXX;
- DCCCCLIIII - XXX = DCCCCXXXXXIIII - XXX = DCCCCXXIIII;

- The numeral C should not repeat itself more than 3 times in a row, rewrite:
- DCCCCXXIIII = CMXXIIII;
- The numeral I should not repeat itself more than 3 times in a row, rewrite:
- CMXXIIII = CMXXIV

#### XC + MCMLIII + CCXIX - MCCXLVIII - XC = CMXXIV;

- 90 + 1,953 + 219 - 1,248 - 90 = 924 The Romans did not have the Hindu-Arabic numbers